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ZOJ2972 Hurdles of 110m(DP)
阅读量:391 次
发布时间:2019-03-05

本文共 2280 字,大约阅读时间需要 7 分钟。

???????????????N??????????????????????????????????????????????????????????????????????????

??????????????????????????T??????????????N?M?????N??????????T1?T2?T3?F1?F2????

  • T1??????????
  • T2??????????
  • T3??????????
  • F1???????????????/??
  • F2???????????????/??

???????????????????????????

????????????DP???????????????????dp???dp[i][j]?????i????????j???????????

?????

  • ????dp[0][0] = 0?????0???????0?
  • ??????i????????????
    • ???????????j >= F1??dp[i][j - F1] = min(dp[i][j - F1], dp[i-1][j] + T1)?
    • ?????dp[i][j] = min(dp[i][j], dp[i-1][j] + T2)?
    • ?????dp[i][min(j + F2, M)] = min(dp[i][min(j + F2, M)], dp[i-1][j] + T3)?
  • ??????????dp[N][j]?????????????
  • ?????

    #include 
    using namespace std;typedef long long ll;const int maxn = 2001;const int inf = 0x3f3f3f3f;int main() { int T, n, m; scanf("%d", &T); while (T--) { scanf("%d %d", &n, &m); vector
    t1(n + 1), t2(n + 1), t3(n + 1); vector
    f1(n + 1), f2(n + 1); for (int i = 1; i <= n; ++i) { int T1, T2, T3, F1, F2; scanf("%d %d %d %d %d", &T1, &T2, &T3, &F1, &F2); t1[i] = T1; t2[i] = T2; t3[i] = T3; f1[i] = F1; f2[i] = F2; } vector
    dp(m + 1, inf); dp[0] = 0; for (int i = 1; i <= n; ++i) { vector
    new_dp(m + 1, inf); for (int j = 0; j <= m; ++j) { if (j >= f1[i]) { if (new_dp[j - f1[i]] > dp[j] + t1[i]) { new_dp[j - f1[i]] = dp[j] + t1[i]; } } if (new_dp[j] > dp[j] + t2[i]) { new_dp[j] = dp[j] + t2[i]; } int next_j = min(j + f2[i], m); if (new_dp[next_j] > dp[j] + t3[i]) { new_dp[next_j] = dp[j] + t3[i]; } } dp = new_dp; } int ans = inf; for (int j = 0; j <= m; ++j) { if (dp[j] < ans) { ans = dp[j]; } } printf("%d\n", ans); }}

    ?????

  • ??????????????????T????????N?M???????????
  • DP??????dp[j]?????i???????j?????
  • ?????????????????????DP???
  • ?????????????????????
  • ????????????????????????????????

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